I know, I have already read enough postings here on Diamond Ring to know that it is almost impossible to identify a gem stone by a picture but I am curious :-)
I just bough this ring on eBay. Somehow the design fascinates me though it is not my usual style. The seller didn't know what the stones are but the ring is said to be 18 k white gold. I can't think of anything but glass or tourmaline that could be that dark green, can you? I only paid $42 so no harm done if it is glass. I am just wondering why someone would set glass in 18 k gold so I am leaning more towards tourmaline.
I am trying to post the pictures from the posting below. You can see how the stones are a bit chipped but I just really like the dark green. I tend to lean towards very dark sapphires too.
My guess would be a synthetic emerald, at least from the pictures. A few simple tests could give you a better idea. Glass is never dichroic, while tourmaline is always strongly dichroic. Emerald is weakly dichroic and not usually enough to see easily. Looking through the stone with a dichroscope and testing the Refractive Index would be enough to tell you what the stone is. Sapphire is never that color of green, (at least I've never seen or heard of one), and is also strongly dichroic.
Thank you, Michael. That sounds so simple. I think I need to get myself a dichroscope as my interest in gems only seems to increase.
Do you know of cases where there is a difference in the refractive index between the treated gems and/or synthetic versions? I guess we can't so lucky as to be able to spot a 'fake' just by looking through a dichroscope?
This ring is really beautiful. Tourmalines are characterized by parallel ridges which carries the length of the crystal. Tourmaline aid clarity will help us to go beyond just thinking, in order to take a very broad understanding of reality. It teaches us that we are light beings in physical form and helps us to experience the physical and the spiritual world and to have tourmalines in the jewelry form is much better than anything.